0=-12x^2+1560x-43200

Solution for 0=-12x^2+1560x-43200 equation:

0=-12x^2+1560x-43200

We move all terms to the left:

0-(-12x^2+1560x-43200)=0

We add all the numbers together, and all the variables

-(-12x^2+1560x-43200)=0

We get rid of parentheses

12x^2-1560x+43200=0

a = 12; b = -1560; c = +43200;
Δ = b2-4ac
Δ = -15602-4·12·43200
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{360000}=600$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1560)-600}{2*12}=\frac{960}{24}
=40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1560)+600}{2*12}=\frac{2160}{24}
=90
$